Question

The minimum value of mass 'm' so that the whole system remains in equilibrium is -​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

force on 5 kg block = mg = 50N

for equilibrium

force on mass m = force on 5 kg block

so, force on block "m" = u × N (u= frictional force)

ATQ ,

u. × N. = 50

0.5 × mg = 50

mg = 100

m=10 kg .... (g=10)

hope it's correct

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