the minimum value of x^2-8x+7
Answers
Answered by
4
Answer:
x^2-8x+7
x^2-7x-x+7
x(x-7)-1(x-7)
(x-1) ( x-7)
x= 1,7
Minimum value = 1
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Answered by
15
Answer:
minimum value is 2
Step-by-step explanation:
given that,
x² - 8x + 7
let y = x² - 8x + 7
to get minimum value of the equation it will have to double differentiate the equation with respect to y
so,
dy/dx = d(x² - 8x + 7)/dx
= 2x - 8
now,
d²y/dy² = d(2x - 8)/dy
= 2
so,
The minimum value is 2
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