Math, asked by sakshiagrawal60, 11 months ago

the minimum value of x^2-8x+7​

Answers

Answered by nikiju2709
4

Answer:

x^2-8x+7

x^2-7x-x+7

x(x-7)-1(x-7)

(x-1) ( x-7)

x= 1,7

Minimum value = 1

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Answered by deepsen640
15

Answer:

minimum value is 2

Step-by-step explanation:

given that,

x² - 8x + 7

let y = x² - 8x + 7

to get minimum value of the equation it will have to double differentiate the equation with respect to y

so,

dy/dx = d(x² - 8x + 7)/dx

= 2x - 8

now,

d²y/dy² = d(2x - 8)/dy

= 2

so,

The minimum value is 2

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