Question

The minimum value of x? - 8x +17 is​

Answer 1

the minimum value of x -8x + 17

Answer 2

Answer:

Questions and answers

Question

If x is real, then the minimum value of x^2 - 8x + 17 is

Answer · 47 votes

Let y = x^2 - 8x + 17 = (x^2 - 2· 4· x + 4^2) + 1 = (x - 4)^2 + 1 We know that if x is a real number then x^2> 0 (x - 4)^2> 0 Hence minimum value of y is 0 + 1 = 1