Question

the minimum value of y= x2-4x will exist at x is equals to​

Answer 1

Explanation:

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Answer 2

Concept:

The lowest point on a graph is the minimal value of a function. Your quadratic equation will have a minimal value if it contains a positive term. By graphing the function or by applying one of the two equations, you can determine this minimum value. There are three ways to figure out a quadratic equation's minimal value. Each one of them can be helpful in figuring out the bare minimum.

Given:

Here it is given the equation is $y= x^2-4x$.

Find:

We have to find the minimum value of $y= x^2-4x$ will exist at $x$ is equals to​ what value.

Solution:

According to the question,

$y= x^2-4x$

So, $dy/dx=2x-4$

The minimum value of $y$ should be $0$.

now,

$2x-4=0\\x=2$

Hence the value of $x=2$.(Answer)

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