Question

The minimum value value of (x-2)(x-9) is

Answer 1

x^2 -9x -2x +18

x^2 -11x +18

(x-11/2) ^2 -28 = 0

for minimum value x =11/2

So it's -28

Answer 2

(x - 2) (x -9) = 0
x^2 - 9x -2x +18 =0
x^2 -11x +18 =0
x^2 -2x -9x +18 =0
x( x - 2) - 9( x - 2) =0
( x - 9) ( x - 2) =0
x =9, x = 2
.... thnx.... ✌✌✌