The minimum velocity (in m/s ) with which a car driver must traverse a flat curve of radius 250m and cofficient of friction 0.6 to avoid skidding is [AIEEE-2002]
Answers
Answered by
0
Answer:
see the above attachment
Attachments:

Answered by
2
Explanation:- As centriputal force is balanced by the centripetal force i.e .,frictional force .
- Using the relation
- mv²/r = μR , where R = μg
- ⟹ mv²/r = μmg or v²= μrg
- ⟹v² = 0.6 × 150× 10
- or, V = 30.m/s
______________________________
Similar questions