Question

The minimum velocity with which a car driver must traverse a flat curve of radius of 150m and coefficients of friction is 0.6 to avoid skating is

Answer 1

Answer:

Explanation:

As we learnt in

Skidding of Vehicle on a Level Road -

Frictional force \geq Req. centripetal Force

\mu mg \geq \frac{mv^{2}}{r}

V_{safe}\leq \sqrt{\mu rg}

V_{safe}=Safe vector move

r = radius of curve

\mu= coefficient of friction

- wherein

V_{safe} is the maximum velocity by which vehicle can turn on a circular path of radius r.  

 

 

 

 

For no skidding along curved track,

\nu = \sqrt{0.6\times 150\times 10}=30\ ms^{-1}

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