Chemistry, asked by chaitanya1520, 9 months ago

The minimum voltage required to electrolyse alumina in the Hall-Heroult process is [ Given, Δ G 0 f ( A l 2 O 3 ) = − 1520 k J m o l − 1 ; Δ G 0 f ( C O 2 ) = − 394 k J m o l − 1

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Answered by anubhavpandey7
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This causes liquid aluminium metal to be deposited at the cathode, while the oxygen from the alumina combines with carbon from the anode to produce mostly carbon dioxide. The theoretical minimum energy requirement for this process is 6.23 kWh/(kg of Al), but the process commonly requires 15.37 kWh

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