The minimum work which must be done to compress 16 gm of oxygen at 300k from a pressure of 1.01325×10^3 N/m^2 to 1.01325×10^5 N/m^2 is:
(A)5744 j (B)8622 j (C)3872 j
(D)7963 j
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Answer:
Given that
m
O
2
=16g
P
1
=1.01325×10
3
, P
2
=1.01325×10
5
T=300K
moles of O
2
=
32
16
=0.5
w
max
=nRTln(
P
1
P
2
)
=0.5×8.3×300×ln(
10
3
10
5
)
=0.5×8.3×300×4.6
w
max
=5727J
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