Question

The minum deuiation produced by hallow
prim filled with a wilain liquid
the light ray is also found to be a
refraited at an angle 30 find the
refractive index of liquid

Answer 1

Answer:

Explanation:

in case of minimum deviation r₁ = r₂

∴ A = 2r

A = 2 × 30°

A= 60°

δ= 30°

μ= $\frac{sin\frac{60+30}{2} }{sin\frac{60}{2} }$

=$\frac{sin 45}{sin30}$

= 2/√2

μ=√2 or 1.4

Answer 2

The minimum deviation produced by a hollow prism filled with a certain liquid the light ray is also found to be 30°.

The light ray is also found to be refracted at angle of 30°.

The refrative index of the liquid is

the minimum angle of deviation of the prism is <br>.

A=2r,so A=60°

<br>now,

A=sin(60+30/2) /(60/2)

=sin 45°/sin=30°

=2/√2

= √2