The minute hand in a clock( which is under repair )revolves 330° in an hour. If the time as per my watch and the clock is 1 pm now,what would be the time in that clock (under repair) when my watch is at 5pm?
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Answer:
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Step-by-step explanation:
Let's see the times at which right angles are formed between 5 and 6
Let's take H=5. Hence the two hands will be at right angles between 5 and 6 at
(
5
×
5
±
15
)
12
11
minutes past 5 'o clock
=
(
25
±
15
)
12
11
minutes past 5 'o clock
=
10
×
12
11
minutes past 5 'o clock and
40
×
12
11
minutes past 5 'o clock
=
120
11
minutes past 5 'o clock and
480
11
minutes past 5 'o clock
=
10
10
11
minutes past 5 'o clock and
43
7
11
minutes past 5 'o clock
10
10
11
minutes past 5 comes before 5.30.
43
7
11
minutes past 5 comes between 5.30 and 6. The question is to find out the time between 5.30 and 6 when the hands of a clock will be at right angles. Hence the required time is
43
7
11
minutes past 5
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