the minute hand of a clock is 10 cm long. the area of the face of the clock swept by the minute hand between 9 am to 9:35 am is ...??????
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Answered by
3
according to question:-
r = 10cm
Area of clock = πr×r
=3.14×10×10
=314cm®
area of the face of the clock swept by minute hand in 5min =
=314÷60×5
=26.16 cm®
r = 10cm
Area of clock = πr×r
=3.14×10×10
=314cm®
area of the face of the clock swept by minute hand in 5min =
=314÷60×5
=26.16 cm®
Answered by
0
Answer:
Step-by-step explanation:
According to question:-
r = 10cm
Area of clock = πr×r
=3.14×10×10
=314cm®
area of the face of the clock swept by minute hand in 5min =
=314÷60×5
=26.16 cm
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