The minute hand of a clock is 4 cm long find the average velocity of the tip of the minute hand Btwn 11:00am to 11:30am and Btwn 11:00 am to 11:30 pm
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4
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Between 4 :00 am to 4:30 am
Average speed = Total distance / time
= π r /( 30 × 60 seconds )
=4π/1800
= 0.00698 cm/s
Average velocity = Total displacement/ Time
= 2r / (30 × 60 seconds)
= 8 / 1800
= 0.0044 cm/s
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HERE IS UR ANSWER.....
__________________________
Between 4 :00 am to 4:30 am
Average speed = Total distance / time
= π r /( 30 × 60 seconds )
=4π/1800
= 0.00698 cm/s
Average velocity = Total displacement/ Time
= 2r / (30 × 60 seconds)
= 8 / 1800
= 0.0044 cm/s
HOPE HELPED...
#@®¥@n#
;-)
mahendrachoudhary123:
question asks avg.velocity not speed?
oh i didn't notice you complete ans.
avg. velocity is given too
yep ..
Answered by
2
avg. velocity =displacement/time
360 degree=60min
180 degree =30 minute.
so displacement=2*radius=8cm
time=30 min.
so avg. vel.=8/30 cm/min=4/15=0.266 cm/min
in both the cases avg. velocity will be same and as written above.
am pm don't make difference. because displacement and time matters.
360 degree=60min
180 degree =30 minute.
so displacement=2*radius=8cm
time=30 min.
so avg. vel.=8/30 cm/min=4/15=0.266 cm/min
in both the cases avg. velocity will be same and as written above.
am pm don't make difference. because displacement and time matters.
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