The minute hand of a clock is 8 cm long.Find the area swept by the minute hand between 8.30 am and 9.05 am
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in 1 min , minute hand travels 6 degree ,
so in 35 min it travels 35× 6 degrees ie 210 degree
now angle in minor sector of the circle formed by minute hand is 360-210 =150 degrees
so area of minor sector = theta / 360 × π r^ 2
substitute the values
ie 150/ 360 × 22/7 × 8× 8 =83.80
now find the area of circle and subtract the area of minor sector from it u will get the area swept by the minute hand .
area of circle = 22/7 × 8×8 = 201.14
now area swept = 201.14 - 83.80=117.34 cm^2
hope this helps my frnd.
so in 35 min it travels 35× 6 degrees ie 210 degree
now angle in minor sector of the circle formed by minute hand is 360-210 =150 degrees
so area of minor sector = theta / 360 × π r^ 2
substitute the values
ie 150/ 360 × 22/7 × 8× 8 =83.80
now find the area of circle and subtract the area of minor sector from it u will get the area swept by the minute hand .
area of circle = 22/7 × 8×8 = 201.14
now area swept = 201.14 - 83.80=117.34 cm^2
hope this helps my frnd.
ram188:
thanx u helped me alot
welcome its my pleasure
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Hope it helps you
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