Question

the minute hand of a clock is 9 cm long find the distance that the tip of the minute hand will move in 45 minutes​

Answer 1

Answer:

Step-by-step explanation:

Area =theta/360xpixrxr

270/360x22/7x9x9

Ans=191

Answer 2

Answer:

= 42 .405 cm

Step-by-step explanation:

Since the height of minute hand is 9 cm

Assuming the clock as a circle.

∴ the radius of circle ( r) =  9 cm

Circumference of circle = 2 π r = 2 * π * 9 = 56.54 cm

When minute hand move 45 minute distance moved tip = $\frac{3}{4}$ of circle .

So the circumference of $\frac{3}{4}$ of circle =   $\frac{3}{4}$ * 56.54  = 42 .405 cm