The minute hand of a clockis 10.5 cm long. Find the area swept by it in 15 minute
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Answered by
4
Angle made by minute hand in 15 minutes = 15×360/60
= 15×6
= 90°
Area of sector = ∅/360×πr²
= 90/360×22/7× 10.5 × 10.5
= 86.725cm²
= 15×6
= 90°
Area of sector = ∅/360×πr²
= 90/360×22/7× 10.5 × 10.5
= 86.725cm²
Answered by
0
Answer:
The area swept by the minute hand is 86.625 cm²
Step-by-step explanation:
∅ = 360/60 = 6.
Angle covered in 15 minutes = 15×6 = 90°
Area of the sector swept by the minute hand = ∅/360 × πr² = 90/360 × 22/7 × (10.5)² = 693/8 = 86.625 cm².
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