the minute hand of a wall clock is 10 cm long find its displacement and the distance covered from 10 a.m. to 10:45 a.m.
Answers
Answer:
DISTANCE = 47.1CM , DISPLACEMENT = 35.7CM
Explanation:
Here R=10cm
Let's break it into two parts,
From 10 am to 10.30 am minute hand rotates 180° from 0 minute to 30 minutes.
Hence distance covered is half the circle means semi circle.
distance= perimeter of semi circle
distance(1) = πR = 3.14×10= 31.4 cm
now 1/4th of circle covers distance 10.30AM to 10.45 AM i.e. 90 degree.
SO, distance(2) = πr/2 = 31.4/2 = 15.7cm
Total distance = 31.4+15.7 = 47.1cm
Displacement is shortest distance between two points.
i.e. distance between 10.00 and 10.45 in clock wise direction.
displacement is twice the length of the hand
Displacement= 2×r= 2× 10= 20cm
1/4 distance between 10.30 to 10.45 = 15.7cm
total displacement, = 20+15.7cm = 35.7cm
I HAVE JUST TRIED TO ANSWER THE QUESTION TO MY BEST.
MUST COMMENT ME FOR ANY ERROR YOU FOUND IN ANSWER AS I WANT TO KNOW MY MISTAKE.
PLZ LIKE AND MARK MY ANSWER AS BRAINLIEST IF YOU FOUND MY ANSWER HELPFUL.