Physics, asked by anima03121979, 1 month ago

the minute hand of a wall clock is 10 cm long find its displacement and the distance covered from 10 a.m. to 10:45 a.m.​

Answers

Answered by RabiUdgata
3

Answer:

DISTANCE = 47.1CM , DISPLACEMENT = 35.7CM

Explanation:

Here R=10cm

Let's break it into two parts,

From 10 am to 10.30 am minute hand rotates 180° from 0 minute to 30 minutes.

Hence distance covered is half the circle means semi circle.

distance= perimeter of semi circle

distance(1) = πR = 3.14×10= 31.4 cm

now 1/4th of circle covers distance 10.30AM to 10.45 AM i.e. 90 degree.

SO, distance(2) =  πr/2 = 31.4/2 = 15.7cm

Total distance = 31.4+15.7 = 47.1cm

Displacement is shortest distance between two points.

i.e. distance between 10.00 and 10.45 in clock wise direction.

displacement is twice the length of the hand

Displacement= 2×r= 2× 10= 20cm

1/4 distance between 10.30 to 10.45 = 15.7cm

total displacement, = 20+15.7cm = 35.7cm

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