Question

the minute hand of a wall clock is 7 cm what distance will it cover in one day​

Answer 1

Answer:

1056 cm

Step-by-step explanation:

The length of this minute hand forms the radius of the circle in which the hand sweeps;

Therefore the distance covered by the tip of the minute hand in one sweep is;

$C=2*\pi *r\\C=2*\frac{22}{7}*7\\ C=44cm$

one sweep covers 44 cm

One sweep of the minute hand of a clock implies one hour.

0ne day has 24 hours, therefore in one day the minute hand does 24r complete sweeps on the clock dial.

The distance covered in a day is given as;

$24*44=1056 cm$

or 1.056 metres

Answer 2

It will cover 63360 cm in 1 day .

Step-by-step explanation:

1 day = 24 hours

1 hour = 60 minutes

24 hours = $24 \times 60 =1440 minutes$

So, 1 day = 1440 minutes

So, minute hand will complete 1440 rotations

Length of minute hand = 7 cm

Distance traveled in 1 rotation = $2 \pi r = 2 \times \frac{22}{7} \times 7 = 44 cm$

Distance traveled in 1440 rotations =$44 \times 1440 = 63360 cm$

Hence it will cover 63360 cm in 1 day .

#Learn more :

The minutes hand of a clock is 9 cm and that of hour hand is 7 cm. if they run for 3 days, how much distance is covered by both the hands

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