Question

The minute hand of clock is 8cm long. Find the area swept by the minute hand between 8.30 a.m and 9.05 a.m .

Answer 1

Minute hand = 8cm = radius of circle(r)
There are 12 divisions in a clock, so each division is 360/12= 30 degrees
From 8:30-9:05, the minute hand sweeps over 7 divisions = 30*7= 210 degrees
Area of section of a circle = (θ/360) * πr^2
 = (210/360) * (22/7) * 8 * 8
 = 117.33 sq.cm.

Answer 2

Answer:

$117.226cm^2$

Step-by-step explanation:

We are given that The minute hand of clock is 8 cm long.

We are supposed to find the area swept by the minute hand between 8.30 a.m and 9.05 a.m .

Minutes between  8.30 a.m and 9.05 a.m . = 35 minutes

60 minutes = 360°

1 minute = $\frac{360}{60}$ = 6°

35 minutes = 35*6 = 210°

Formula of area of sector = $\frac{\theta}{360^{\circ}}\times \pi \times r^2$

Substitute the values.

Area   = $\frac{210}{360}\times 3.14 \times (8)^2$

          = $117.226cm^2$

Hence the area swept by minute hand is $117.226cm^2$