The mixture of 80 liter of acid and water contains 20 liters of acid what percentage of water is there in the mixture
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total volume of mixture = 80 liters
volume of acid = 20 liters
volume of water = total volume of mixture - volume of acid = 80 -20 = 60 liters
% of water in mixture = volume of water × 100 / total volume of mixture
= 60 × 100 /80 = 75%
hence percentage of water in the mixture is 75%
prirajput2003:
Exactly
Excellent
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