the mixture of water and glycerol with water 50% by weight and glycerol 50% by weight what is the weight density of the total mixture if the density of water is 1gm/cc and that of glycerol is 1.36 gm/cc
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let the total weight of the mixture = m gram
mass of glycerol = 50% of m = 0.5m gram
density of glycerol = 1.36 g/cc
volume of glycerol = 0.5m/1.36 cc
mass of water = 50% of m = 0.5m gram
density of water = 1 g/cc
volume of glycerol = 0.5m/1 cc = 0.5m cc
total volume = 0.5m + (0.5m/1.36)
= 0.5m(1+1/1.36)
= 0.5m(1.735)
=0.8675m cc
Density of mixture = mass/volume
= m/0.8675m
= 1.15 g/cc
mass of glycerol = 50% of m = 0.5m gram
density of glycerol = 1.36 g/cc
volume of glycerol = 0.5m/1.36 cc
mass of water = 50% of m = 0.5m gram
density of water = 1 g/cc
volume of glycerol = 0.5m/1 cc = 0.5m cc
total volume = 0.5m + (0.5m/1.36)
= 0.5m(1+1/1.36)
= 0.5m(1.735)
=0.8675m cc
Density of mixture = mass/volume
= m/0.8675m
= 1.15 g/cc
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