Question

The mode of data 1, 3, 12, 10, 8, 4, 5, 4, 3, 2, 1, 4 is 60 ÷ k. Find the sum of digits of k *

Answer 1

Answer:

Highest frequency 12 , Modal class =40−60

Mode =I+2f1−f0−f2f1−f0×h

Where ,

I= lower limit of the modal class =40

f1= frequency of modal class =12

f2 frequency of class after the modal class =6

f0 frequency of class before the modal class =10

h= class width =20

putting the values in the equation 

Mode=50

Answer 2

Solution :

Highest frequency 12 , Modal class = 40−60

Mode = l+ f1 − f0/ 2f1 − f0 - f2 ×h

Where ,

I = lower limit of the modal class = 40

f1 = frequency of modal class = 12

f2 = frequency of class after the modal class = 6

f0 = frequency of class before the modal class = 10

h = class width = 20

putting the values in the equation

Mode = 50.