Question

The mode of the following data is 36.find the missing frequency x in it.Class  0-10  10-20  20-30  30-40  40-50  50-60  60-70Frequency  8  10  x  16  12  6  7

Answer 1

therefore the answer is 10 ,.hope this answer helps you

Answer 2

Answer:

The value of x=10.

Step-by-step explanation:

Given : Data,  

Class :      0-10  10-20  20-30  30-40  40-50  50-60  60-70

Frequency : 8       10       x            16       12         6            7

To find : The value of x?  

Solution :  

Formula to find the mode is  

$M=l+(\frac{f_1-f_0}{2f_1-f_0-f_2})\times h$  

Where, l is the lower limit of the modal class  

h is the size of the class interval,  

$f_1$ is the frequency of the modal class  

$f_0$ is the frequency of the class preceding the modal class,  

$f_2$ is the frequency of the class succeeding the modal class.  

From the given data,  

In the class interval 30-40 has highest frequency.  

So, The modal class is 30-40  

l=30 , h=10 , $f_1=16$ ,$f_0=x$, $f_2=12$ , M=36

Substituting the value in the mode formula,  

$36=30+(\frac{16-x}{2(16)-x-12})\times 10$  

$36-30=(\frac{16-x}{32-x-12})\times 10$  

$6=\frac{160-10x}{20-x}$  

$120x-6x=160-10x$  

$4x=40$  

$x=10$  

Therefore, The value of x=10.