Question

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)

Class  Frequency

0-10 3

10-20 X

20-30 15

30-40 Y

40-50 8

50-60 4



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Answer 1

Answer:

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 3

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 310-20 X

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 310-20 X20-30 15

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 310-20 X20-30 1530-40 Y

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 310-20 X20-30 1530-40 Y40-50 8

The mode of the following distribution is 26.Find the missing frequency if total frequency is 50                                                                            (4M)Class  Frequency0-10 310-20 X20-30 1530-40 Y40-50 850-60 4

Answer 2

Answer:

X = 9
Y = 11

Solution:

The maximum frequency is 15.

The mode class is 20-30.

L= = lower boundary point of mode class = 20

f1 = frequency of the mode class
= 15

f0 = frequency of the preceding class
= 9

f2 = frequency of the succedding class
= 11

c = class length of mode class = 10


Mode = L + (f1 - f0/2 * f1 - f0 - f2) * c

= 20 + (15 - 9/2 * 15 - 9 - 11) * 10

= 20 + (6/10) * 10

= 20 + 6

= 26

Hope this will be helpful to you.