Math, asked by Aditiiiiiiiiiii, 8 months ago

The mode of the following distribution is ` 66.
What would be the median wage?


(X): 30–40, 40–50, 50–60, 60–70, 70–80, 80–90


(f): 8, 16, 22, 28, 24, 12


(a) 64.00
(b) 64.56
(c) 62.32 ✔️
(d) 64.25

Please give full Solution ​

Answers

Answered by Siddharta7
35

Answer:

Option(C)

Step-by-step explanation:

x                      f              cf

30 - 40             8            8

40 - 50            16            24

50 - 60            22           46

60 - 70            28           74

70 - 80            24           98  

80 - 90            12             110

                      ------

                     110

Now,

N/2 = 110/2 = 55

The cumulative frequency just greater than N/2 is 74, so then the median class is (60 - 70) such that l = 60, f = 28, F = 46, h = 10.

So,

Median = l + [(N/2 - F)/f] * h

            = 60 + [(55 - 46)/28] * 10

            = 63.2

Hope it helps!

Answered by devikagopan2445
6

Step-by-step explanation:

answer will be

median = 63.2

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