The mode of the following frequency distribution is 55, find the values of x and y, if the total frequency is 50.
C.I
0-15
15-30
30-45
45-60
60-75
75-90
f
6
7
y
15
10
x
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C.I frequency 0-15 6 15-30 7 30-45 k(f1) 45-60 15(f0) 60-75 10(f2) 75-90 8 51Given that
mode of frequency distribution is 55
Here given
mode =55
So
mode class is 45−60
lower limit (t) =45
class height (h) =15
then
f0=15
f1=k
f2=10
mode =l+(2f0−f1−f2f0−f1)×h
55=45+(2×15−k−1015−k)×15
55−45=(30−k−1015−k)×15
10(30−k−10)=(15−k)15
10(20−k)=215−15k
200−10k=225−15k⇒15k−
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