Question

the modulus of (1+1/i)^2 is​

Answer 1

Answer:

-2i

Step-by-step explanation:

(1+1/i)²

Using (a+b)²=a²+b²+2ab

=1²+(1/i)²+2*1*1/i

=1+(1/i²)+2/i

=1+(1/-1)+2/i

=1-1+2/i

=2/i

Multiplying and dividing by i

=2*i/i*i

=2i/i²

=2i/-1

=-2i