Question

The modulus of 2+i/4i+(1+i)^2?​

Answer 1

Answer:

Solution

verified

Verified

=

4i+(1+i)2

2+i

⇒

4i+1−1+2i

2+i

6i

2+i

3i

1

+

6

1

6

1

−

3

i

z=

6

1

−

3

i

∣z∣=

36

1

+

9

1

=

6

5

principal Arg(2)= πtan

−1

(

V6

−V

3

)πtan

−1

(−2)

=π−tan

−1

(2)

=π−63.44

and arg(2)=2Kπ+π−63.44

=2(K+1)π−63.44

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