Question

the modulus of the vector 19i+5j-6k is​

Answer 1

$|vector \: a| = \sqrt{19 {}^{2} + 5 {}^{2} + ( - 6) {}^{2} } \\ = \sqrt{361 + 25 + 36} = \sqrt{422}$

Answer 2

The modulus of the vector 19i+5j-6k is​  20.54.

We know, the magnitude or modulus of a vector represented by A = ai + bj + ck is

|A| = √(a² + b² + c²)

The vector given to us is 19i + 5j - 6k.

If we compare this vector with ai + bj + ck, we get:

a = 19

b = 5

c = -6

As we know, modulus was equal to √(a² + b² + c²)

Putting the respective values of a, b and c, we get:

Modulus = √(19² + 5² + (-6)²)

               = √(361 + 25 + 36)  = √(422) = 20.54