The molal depression constant of water is 1.86 K. Kg. mol-1
. Calculate the depression in freezing
point of 0.1 molal aqueous urea solution. (molar mass of urea = 60 g / mol)
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Answer:
Depression in freezing point is given by
ΔT
f
=i×K
f
×m
ΔT
f
=T
f
o
−T
f
i= Vant hoff factor =1 (for non electrolyte)
K
f
=1.86K/m
m= Molality
ΔT
f
=i×K
f
×
weight of solvent in kg
moles of solute
Moles of solution (urea) =0.02
Molar mass of solute (urea) =60g/mol
Weight of solvent (water) =100g=0.1kg
(T
f
0
−T
f
)=1×1.86×
0.1kg
0.02
(0−T
f
)
o
C=0.372
T
f
=−0.372
o
C
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