Question

the molal depression of freezing point of water is 1.86 degree Celsius per thousand gram of water .0.02 mole of Urea dissolved in hundred gram of water will produce a lowering of temperature​

Answer 1

Explanation:

Depression in freezing point is given by

ΔT

f

=i×K

f

×m

ΔT

f

=T

f

o

−T

f

i= Vant hoff factor =1 (for non electrolyte)

K

of solute

Moles of solution (urea) =0.02

Molar mass of solute (urea) =60g/mol

Weight of solvent (water) =100g=0.1kg

Answer 2

0.372 degree is the right answer.

Refer attachment!!!