Chemistry, asked by pratham1892, 1 year ago

the molality of 648 gram of pure water is​

Answers

Answered by Anonymous
75

We know that,

Molality = moles of solute / mass of solvent in kg

No of moles= given mass/molar mass

=648/18==36mole

Here's, mass of solvent in kg will be 648×10^-3

So, molality = 36/648×10^-3 = 55.56 molal


Anonymous: hyy hii
Answered by gadakhsanket
49

Hey Dear,

◆ Answer -

Molality = 55.56 m

◆ Explanation -

In pure water, both solute & solvent is water.

Moles of solute is calculated by -

Moles of solute = mass of solute / molar mass

Moles of solute = 648 / 18

Moles of solute = 36 moles

Molality of solution is calculated by -

Molality = Moles of solute / mass of solvent

Molality = 36 / 0.648

Molality = 55.56 m

Therefore, molality of 648 g pure water is 55.56 m.

* Molality of pure water is independent of its mass.

Hope this is helpful..

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