the molality of 648 gram of pure water is
Answers
Answered by
75
We know that,
Molality = moles of solute / mass of solvent in kg
No of moles= given mass/molar mass
=648/18==36mole
Here's, mass of solvent in kg will be 648×10^-3
So, molality = 36/648×10^-3 = 55.56 molal
Anonymous:
hyy hii
Answered by
49
Hey Dear,
◆ Answer -
Molality = 55.56 m
◆ Explanation -
In pure water, both solute & solvent is water.
Moles of solute is calculated by -
Moles of solute = mass of solute / molar mass
Moles of solute = 648 / 18
Moles of solute = 36 moles
Molality of solution is calculated by -
Molality = Moles of solute / mass of solvent
Molality = 36 / 0.648
Molality = 55.56 m
Therefore, molality of 648 g pure water is 55.56 m.
* Molality of pure water is independent of its mass.
Hope this is helpful..
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