Question

The molality of 90% (w/v) H2SO4 solution is? (density=1.8 gm/ml)

Answer 1

molarity = %(w/v)×10/Mw


= 90×10 /98

now

morality = M×1000/ 1000d - M×
Mw

= 900/98×1000 / 1000×1.8 -900/98×98

= 10.20 m

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Answer 2

Explanation:

The molaity of 90% H2SO4 solution is density = 1.8 gm/ mol

The density of solution = 1.8gm/mol

weight of one litre of solution = 1800gm

weight of H2SO4 in the solution

== 1800×90/100

== 1620 gm

weight of solution is 1800-- 1620 = 180 gm

Molaity is , = 1620/98 × 1000/180

== 91.83 M

I HOPE IT IS RIGHT