the molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is
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wrong question
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The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is 0.04 mol/kg
Explanation:
- Molality of a solution (m) =
Number of moles of solute Formula 1
Mass of solvent (in kg)
- To calculate number of moles present in 1.8 g of glucose we use the formula: -
No. of moles = Mass of solute/Mass of one mole
- We already know mass of solute = 1.8 g
- We have to calculate mass of 1 mole of glucose
- Chemical formula for glucose is C₆H₁₂O₆
We know that
atomic mass of C is 12 u
atomic mass of H is 1 u
atomic mass of O is 16 u
- Putting the values in chemical formula of glucose we get mass of 1 mole of glucose as 180 g.
- So no. of moles of glucose in 1.8 g glucose = 1.8/ 180
=0.01 moles
- We now put the values in formula 1
Molality = 0.01 /0.25 ( 250 g is 0.25 kg)
=0.04 mol/kg
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