Question

the molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is​

Answer 1

Answer:

wrong question

Explanation:

Answer 2

Answer:

The molality of a solution containing 1.8 g of glucose dissolved in 250 g of water is 0.04 mol/kg

Explanation:

• Molality of a solution (m) =

        Number of moles of solute             Formula 1

          Mass of solvent  (in kg)

• To calculate number of moles present in 1.8 g of glucose we use the formula: -

          No. of moles  =    Mass of solute/Mass of one mole      

• We already know mass of solute = 1.8 g

• We have to calculate mass of 1 mole of glucose    
• Chemical formula for glucose is C₆H₁₂O₆

                 We know that

        atomic mass of C is 12 u

        atomic mass of H is 1 u

        atomic mass of O is 16 u

•  Putting the values in chemical formula of glucose we get mass of 1 mole of glucose as 180 g.

•       So no. of moles of glucose in 1.8 g glucose = 1.8/ 180

                                                                        =0.01 moles

• We now put the values in formula 1

      Molality = 0.01 /0.25     ( 250 g is 0.25 kg)

                     =0.04 mol/kg