Question

The molality of a solution containing 3g ch3cooh in 50 g benzene is

Answer 1

Explanation:

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Answer 2

Molality of a solution containing 3g $CH_3COOH$ in 50 g benzene is 1m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molality=\frac{n\times 1000}{W_s}$

where,

n = moles of solute =$\frac{\text{Given mass}}{\text{Molar mass}}=\frac{3g}{60g/mol}=0.05moles$

$W_s$ = weight of solvent (benzene) in g  = 50 g

Now put all the given values in the formula of molarity, we get

$Molality=\frac{0.05moles\times 1000}{50g}=1mole/kg$

Thus molality of a solution is 1m

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