The molality of a solution of NaoH is 5 molal.The density of solution is 1.4 gm/ml.Calculate the molarity of solution.
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Answer:
2.97 M
Explanation:
Molality of NaOH solution =3 m
Molality=number of moles of solute/mass of solvent(kg)
3 = n / mass of ssolven
mass of solvent = 3 / 1000n
Also, number of moles=mass/molar mass
Density of solution,ρ=1.110g/mL
Mass of 1 mL solution = 1.11g=m solute +m solvent
n×40+1000n / 3 = 1.11
n=2.97×10-³ mol
Molarity = number of moles of solute/ volume of solution(L)
M= 2.97×10-³ / 0.001 = 2.97M
Answer= 2.97M
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