Chemistry, asked by satapathyamreshkumar, 3 months ago

The molality of a solution of NaoH is 5 molal.The density of solution is 1.4 gm/ml.Calculate the molarity of solution.

Answers

Answered by gargs4720
1

Answer:

2.97 M

Explanation:

Molality of NaOH solution =3 m

Molality=number of moles of solute/mass of solvent(kg)

3 = n / mass of ssolven

mass of solvent = 3 / 1000n

Also, number of moles=mass/molar mass

Density of solution,ρ=1.110g/mL

Mass of 1 mL solution = 1.11g=m solute +m solvent

n×40+1000n / 3 = 1.11

n=2.97×10-³ mol

Molarity = number of moles of solute/ volume of solution(L)

M= 2.97×10-³ / 0.001 = 2.97M

Answer= 2.97M

Answered by jaanvigarg16790
0

Answer:

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