Question

The molality of a sulphuric acid in its aqueous solution is 1 mol/kg. The total mass of the solution
which contains 1 kg of solvent
(1) 1902 g
(2) 902 g
(3) 1098 g
(4) 1001 g​

Answer 1

Answer:

Solution is in the above attachment

Ans: option( 3)

Answer 2

Answer:

3) 1098g

Explanation:

Molarity of a sulphuric acid in its aqueous solution = 1 mol/kg (Given)

Molality = Moles of solute / Mass of Solvent

1 = Moles of solute / (1 kg)

Moles of solute = 1 mol

Mass of solute = Moles of solute × Molar mass of solute

= 1 × 98 [ This is because the molar mass of H₂SO₄( sulphuric acid) is 98 g/mol]

= 98 g

Thus,

Mass of the solution = Mass of solute + Mass of solvent

= 09 g + 1000g

= 1098

Therefore, the total weight of the solution is 1098 grams.