Question

The molality of a sulphuric acid solution is 0.2. Calculate the total weight of the solution having 1000g of solvent

Answer 1

1019.6g is the mass of solution
Since 0.2 moles of H2SO4 is present in 1000g(1kg) of solvent
Mass of sulphuric acid will be
98 g/mol ×0.2 mol which is 19.6g
Add this mass to the mass of the solvent giving you the total mass of solution

Answer 2

Answer:

1019.6 g

Explanation:

molality = number of moles of solute / mass of solution (in kg)

0.2 = n/1

∴n=0.2 moles

one mole of h2so4 contains 98 g

∴ 0.2 moles contain 19.6g h2so4

here we are asked for the total weight of solution

so, the answer is 1000+19.6  = 1019.6 g

Thanks