Question

The molality of a sulphuric acid solution is
0.6 mol/kg. The total weight of the solution if
amount of solvent is 1 kg​

Answer 1

0.6 kg

1 kg

1/0.6 =6.1 kg ans

Answer 2

Answer:

Molality = Moles of solute / Mass of Solvent

0.6 = Moles of solute / (1 kg)

Moles of solute = 0.6 mol

Mass of solute = Moles of solute × Molar mass of solute

= 0.6 × 98 ……[∵ Molar mass of H₂SO₄ is 98 g/mol]

= 58.8 g

Mass of solution = Mass of solute + Mass of solvent

= 58.8g + 1000g

= 1058.8 g

Total weight of the solution is 1058.8 grams.

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