Question

the molality of aqueous NaoOH solution having 0.1 mole fraction of NaOH is?
5.13
6.17
7.25 or
4.43​

Answer 1

Answer:

here!

Explanation:

molarity (m)=(1-mole fraction of solute)×molecular mass of solventmole fraction of solute×1000​

m=(1−0.1)(18)0.1×1000​

m=6.1728

We know, Relationship between molarity (m)

And molarity (m) is

m1​=md​−1000molecular mass of solute​

6.17281​=M1.4​−100040​

M1.4​=6.17281​+100040​

M1.4​=0.202

M=0.2021.4​=6.9