Question

the molality of glucose when "0.015" moles of glucose dissolved in 30g of water​

Answer 1

Answer:

m=no moles of solvent×1000 /mass of solvent(gm)

Explanation:

m=0.015×1000/30=0.5

Answer 2

Given:

Moles of glucose = 0.015

Quantity of water = 30g

To Find:

Molality of Glucose when dissolved in water

Solution:

Molar mass of water = 18 gm

Moles of water = 30/18 = 1.66  

Molar mass of glucose = 180 gm

​Moles of glucose = 0.015

Molality = moles of solute × 1000/ Mass of solvent

Molality = 0.015 × 1000/30

= 0.5

Answer: The molality of glucose is  0.5 mol / kg