The molanty of the solution obtained by mixing 200 ml of 2 M KOH with 800 ml of 4 M KOH
solution will be
A)2.6 M
B)4.2 M
C)1.8M
D)3.6M
Answers
Explanation:
Explanation:Given : Molarity of H
2
SO
4
= 18M
As, Molarity =
volume of solution
no. of moles of solute
i.e., 18moles of sulphuric acid is present per litre of solution.
Density=1.8g/mL {given}
Thus , mass of one litre of this solution ,
Density =
volume
mass
mass = density×volume
mass = 1.8×1000
mass = 1800g
Thus , mass of 1litre 18M H
2
SO
4
solution is 1800g or 1.8kg.
Now, mass of solution = mass of solute + mass of solvent
mass of solution = no. of moles of solute X molar mass of solute + mass of solvent
1800 = 18×98 + mass of solvent
mass of solvent = (1800−1764)g
mass of solvent = 36g
Now , molality of H
2
SO
4
solution is given by,
molality =
massofsolvent(inkg)
numberofmolesofsolute
molality =
36
18×100
molality = 500m
Hence, the molality of H
2
SO
4
solu
is 500m.
I hope it helps you ✌️