Chemistry, asked by preetkomal0473, 2 months ago

the molar conductance at infinite dilution of Nal, ch3coona, and (ch3coo)2mg are 10.59,7.10 and 16.58 scm2 mol-1 respectively at 298k. calculate the molar conductance of Mgl2 at infinite dilution??

Answers

Answered by rohitchatterjee420

Answer:

this is the answer...

Explanation:

The molar conductivity of NaCl,HCl and CH3COONa at infinite dilution are 126.45,426.16 and 91 Scm2mol−1 respectively. The molar conductivity of CH3COOH at infinite dilution is 390.71 Scm2mol−1.

The calculations are as shown below:

λCH3COOH∞ = λCH3COONa +λHCl −λNaCl

λCH3COOH∞=91 Scm2mol−1+426.16 Scm2mol−1−126.45 Scm2mol−1

λCH3COOH∞=390.71 Scm2mol−1

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the molar conductance at infinite dilution of Nal, ch3coona, and (ch3coo)2mg are 10.59,7.10 and 16.58 scm2 mol-1 respectively at 298k. calculate the molar conductance of Mgl2 at infinite dilution??​

Answers

the molar conductance at infinite dilution of Nal, ch3coona, and (ch3coo)2mg are 10.59,7.10 and 16.58 scm2 mol-1 respectively at 298k. calculate the molar conductance of Mgl2 at infinite dilution??