The molar conductance of nacl hcl and ch3coona at infinite dilution are 126.45, 426.16
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Answer:
Explanation:
Λ
NaCl
=Λ
Na
+
+Λ
Cl
−
Λ
HCl
=Λ
H
+
+Λ
Cl
−
Λ
CH
3
COONa
=Λ
Na
+
+Λ
CH
3
COO
−
Let,Λ
Na
+
=x,Λ
Cl
−
=y,Λ
H
+
=z,Λ
CH
3
COO
−
=w
Given,
x+y=126.45
y+z=426.16
x+w=91
From the above 3 equations, value of z+w=390.71\\z+w=390.71
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