Question

The molar conductivity of 0.025 mol/L methanoic acid is 46.1 sm^2/mol.calculate its degree of dissociation & dissociation constant.

Answer 1

Answer:

The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1 . The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1. Calculate its degree of dissociation and dissociation constant. Given λ ° (H+) = 349.6 S cm2 mol−1 and λ ° (HCOO−) = 54.6 S cm2 mol.follow me insta dad_of__devil_383..

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