The molar conductivity of 0.05 M BaCl2 solution at 25° is 223-1 cm2 mol -1. What is its conductivity
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Explanation:
used this for ula to get ur anwer.
molar conductivity = kappa(conductivity) * 1000/ M
conductivity = 223*0.05/1000
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Answer:
The molar conductivity of 0.05 M BaCl2 solution at 25° is 223-1 cm2 mol -1. What is its conductivity
Explanation:
The molar conductivity of 0.05 M BaCl2 solution at 25° is
cm2
-1. What is its conductivity
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