Question

The molar conductivity of 0.05 molar bacl2 solution at 25 degree celsius is 223 per ohm cm² per mole what is it's conductivity

Answer 1

The molar conductivity of OH- is 3-5 times the conductivity of other small anions. To calculate the conductivity of a solution you simply multiply the concentration of each ion in solution by its molar conductivity and charge then add these values for all ions in solution.

Answer 2

The conductivity of a solution with molar conductivity of 0.05 molar bacl2 solution at 25 degree celsius is 223 per ohm cm² per mole is $1.115 Sm^{2}$.

Explanation:

The given data is as follows.

      molarity (m) = 0.05 molar,    

molar conductivity ($\lambda_{m}$) = 223 $\ohm^{-1} cm^{2}/mol$ = 0.0223 $\ohm^{-1} m^{2}/mol$

     conductivity ($\kappa$) = ?

We know that the relation between molar conductivity and conductivity is as follows.

           $\lambda_{m} = \frac{\kappa \times 1000}{\text{molarity}}$

0.0223 $\ohm^{-1} cm^{2}/mol = \frac{\kappa \times 1000}{0.05 M}$  

                $\kappa = 1.115 S m^{2}$