Question

the molar conductivity of 0.25M solution of kcl at 300k is 100s cm^2 mol^-1 . the conductivity of solution in S cm-1

give ans with solution I will give you brainlist
​

Answer 1

Given:

Molar conductivity = 100cm²

Quantity of solution = 0.25M

Temperature = 300k

To Find:

The conductivity of the solution

Solution:

Converting the temperature = K = 0.0300 S cm−1  

C = 0.25 M

Using the formula of molar conductivity -  

Λm = ( k × 1000)/M

Λm =(0.0300 × 1000 )/0.25

Λm = 120 cm2 mol−1

Answer: The conductance of the solution is 120 cm² mol−1

Answer 2

The value of conductivity is Λm = 120 Cm^2 / mol

Explanation:

We are given that:

• Molarity of solution = 0.25 M
• Molar conductivity of solution = 100 cm^2 / mol
• Temperature = 300 K

To Find: Conductivity = ?

Solution:

The formula of conductivity

Λm = ( k × 1000)/M

Now K = 300 / 10000 = 0.03 S /cm

Λm = 0.03 x 1000 / 0.25

Λm = 0.03 x 4000

Λm = 120 Cm^2 / mol

Thus the value of conductivity is Λm = 120 Cm^2 / mol