Question

The molar conductivity of a 0.5 mol/dm³ solution of AgNO₃ with electrolytic conductivity of 5.76 x 10⁻³ S cm⁻¹ at 298 K is
(1) 2.88 Scm² /mol
(2) 11.52 Scm² /mol
(3) 0.086 S cm² /mol
(4) 28.8 Scm² /mol

Answer 1

Answer:

(2)11.52Scm^2/mol

Explanation:

c is 0.5 mol/dm^3T= 298ko

lamda =k *1000/m

=5.76*10^-3/0.5

=11.52Scm^2/mol