Question

The molar conductivity of a solution of a weak acid HX (0.01 M) is 10 times smaller than the molar conductivity of a solution of a weak acid HY (0.10 M). If $\lambda_{x^-}^0 \approx \lambda_{y^-}^0$ the difference in their p$K_a$ values, p$K_a$(HX) – p$K_a$ (HY), is _______.(consider degree of ionization of both acids to be <<1)

Answer 1

Answer:

it's answer would be 3

Explanation:

-log Ka1=(-log 10-3)+(-log Ka2)

pKa1=3+pKa2

pKa1-pKa2=3